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2019-Mar-24 03:29

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Mar. 11 2019 - 7:04pm
@Den Hey, thanks for all of the support. Finished with the changes and currently playing through the game !!
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Feb. 25 2019 - 7:31pm
@Den Yo, finishing up the bosses and will do some more testing before the big release !!
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Feb. 18 2019 - 10:42pm
@Den Hey, got the main bosses edited and working on the treasure chests. Getting close to finished my edits !!
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@Den Yo, got the shops edited now and will start work on the treasure edits. I bit confused on monster chests ATM...
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@Den Hey, really making progress with my Hex-Editing. Replied to my topic...a bit stuck again
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Jan. 23 2019 - 11:42pm
@Den  Yo, I am really getting the hang of this HEX editing stuff !! Working on figuring out the growth rate formula !!
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@Den I am starting get more understanding about Hex editing.  Thanks for taking time out for me !
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Jan. 15 2019 - 6:45pm
@Den Still working on getting more comfortable with HxD.  Thanks for the encouragement !!

Author Topic: [FFL2] Impressive.. Most Impressive - Question on Seven Sword chance to hit mathematics  (Read 3977 times)

Appiration

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The amount of information contained here about Final Fantasy Legend II (SaGa 2) is staggering!   :o

I've played neoFFL2v4.0 extensively and am very impressed.  I see v.4.1 is out now... have to give it a whirl...

I do have a technical question I've not found an answer to scouring your website and the rest of the web.

Is it mathematically possible to hit Arsenal using a 7 Seven Sword equipped Robot with an AGL of 5 (base) all seven times?

I'm curious if it's a definable point or if it's a limit of X as n->infinity =0 function.   ???
« Last Edit: 2009-Sep-24 09:48 by Appiration »

Den

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I haven't done much testing with multiple hit weapons. However, if it's anything like the single hit formula, 100% - 2 * (AttackerAGL - DefenderAGL), then your robot would never land a single hit. The formula says that a robot with less than 49 agility would always miss against Arsenal. Actually depending on the algorithm, it could be 0% or 1/256. If 1/256, then your chances of hitting all 7 times would be 1/256^7 = 1.3x10^-17. Hence, I have to study at the algorithm closely to see whether it's 0% or close to 0.
« Last Edit: 2009-Sep-25 02:09 by Den »
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